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$\int\frac{6x^3+7x^2+2x+10}{\left(2x-1\right)\left(x+1\right)\left(x^2+2\right)}ddx$
Learn how to solve integral calculus problems step by step online. \int \frac{6x^3+ 7x^2 + 2x + 10 }{\left(2x − 1\right)\left(x + 1\right)\left(x^2+ 2\right)}d. Math interpretation of the question. Simplify the expression inside the integral. Rewrite the fraction \frac{6x^3+7x^2+2x+10}{\left(2x-1\right)\left(x+1\right)\left(x^2+2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(x+1\right)\left(x^2+2\right).