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Solve the inequality $\left(x-2\right)^2+\left(x+4\right)\left(x-2\right)+3x>-1$

Step-by-step Solution

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Final Answer

$x>1$
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Step-by-step Solution

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The product of two binomials of the form $(x+a)(x+b)$ is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: $(x+a)(x+b)=x^2+(a+b)x+ab$

$\left(x-2\right)^2+x^2+\left(4-2\right)x+4\cdot -2+3x>-1$

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$\left(x-2\right)^2+x^2+\left(4-2\right)x+4\cdot -2+3x>-1$

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Learn how to solve problems step by step online. Solve the inequality (x-2)^2+(x+4)(x-2)3x>-1. The product of two binomials of the form (x+a)(x+b) is equal to the product of the first terms of the binomials, plus the algebraic sum of the second terms by the common term of the binomials, plus the product of the second terms of the binomials. In other words: (x+a)(x+b)=x^2+(a+b)x+ab. Subtract the values 4 and -2. Multiply 4 times -2. Combining like terms 2x and 3x.

Final Answer

$x>1$

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Function Plot

Plotting: $x>1$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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