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Step-by-step Solution

Trigonometric integral $\int\tan\left(-1\right)^{}1xdx$

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Answer

${\left(-\frac{31}{20}\right)}^{}\cdot\frac{1}{2}x^2+C_0$

Step-by-step explanation

Problem to solve:

$\int x\:tan\:^{-1}dx$
1

Calculating the tangent of $-1$ degrees

$\int{\left(-\frac{31}{20}\right)}^{}1xdx$
2

Any expression multiplied by $1$ is equal to itself

$\int{\left(-\frac{31}{20}\right)}^{}xdx$

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Answer

${\left(-\frac{31}{20}\right)}^{}\cdot\frac{1}{2}x^2+C_0$
$\int x\:tan\:^{-1}dx$

Main topic:

Integral calculus

Used formulas:

2. See formulas

Time to solve it:

~ 0.65 seconds

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