Final Answer
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Rewrite the fraction $\frac{7x^2+2x-3}{\left(2x-1\right)\left(3x+2\right)\left(x-3\right)}$ in $3$ simpler fractions using partial fraction decomposition
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$\frac{7x^2+2x-3}{\left(2x-1\right)\left(3x+2\right)\left(x-3\right)}=\frac{A}{2x-1}+\frac{B}{3x+2}+\frac{C}{x-3}$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int((7x^2+2x+-3)/((2x-1)(3x+2)(x-3)))dx. Rewrite the fraction \frac{7x^2+2x-3}{\left(2x-1\right)\left(3x+2\right)\left(x-3\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(2x-1\right)\left(3x+2\right)\left(x-3\right). Multiplying polynomials. Simplifying.