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Divide $-181211$ by $100$
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$x^2+40x+1812.11=0$
Learn how to solve quadratic equations problems step by step online. Solve the quadratic equation x^2+40x-181211/100=0. Divide -181211 by 100. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=40 and c=1812.11. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).