$4\left(\frac{x}{8}-2\right)=\frac{1}{4}\left(2x-7\right)$

$9+\frac{8^3}{2}$

$\int\left(3cos^42x\right)dx$

$\lim_{x\to0}\left(\frac{\frac{\pi}{2}-x\left(\sin\left(x-\frac{3\pi}{2}\right)\right)}{\sec\left(x-\frac{\pi}{2}\right)-1}\right)$

$-2y\:+\:14\:_{\:9y\:+\:5}$

$2\left(x-9\right)=-10$

$y^2=4-x$