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Find the derivative of x^3y^2*5+3y^5=pi+x3^0.5

\frac{d}{dx}\left(5x^3 y^2+3y^5=\pi +x\sqrt{3}\right)

Step by step solution

Problem

$\frac{d}{dx}\left(5x^3 y^2+3y^5=\pi +x\sqrt{3}\right)$

Show full step-by-step solution

Answer

$\frac{d}{dx}\left(3y^5+5y^2x^3\right)=\frac{d}{dx}\left(\sqrt{2}x+\pi \right)$

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$\frac{d}{dx}\left(5x^3 y^2+3y^5=\pi +x\sqrt{3}\right)$

Main topic:

Differential calculus

Used formulas:

0

Time to solve it:

0.22 seconds