$-3s=-48$
$\left(6a^2+3b^3\right)^2$
$\lim_{x\to2}\left(\left(x+1\right)^2\right)$
$\left(a^1\right)^2$
$2n^4\cdot4n$
$\frac{6cr^3}{3c^4r^6}$
$7.5+3.8+\left(-2.9\right)-\left(-3.2\right)$
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