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Step-by-step Solution

Solve $\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$

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Answer

$\frac{\left(x-4\right)\left(x+3\right)}{x+2}$

Step-by-step explanation

Problem to solve:

$\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$
1

Simplifying the fraction

$\frac{x^2-16}{x-1}\cdot\frac{x^2+2x-3}{x^2+6x+8}$
2

Multiplying fractions

$\frac{\left(x^2-16\right)\left(x^2+2x-3\right)}{\left(x-1\right)\left(x^2+6x+8\right)}$

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Answer

$\frac{\left(x-4\right)\left(x+3\right)}{x+2}$
$\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$

Main topic:

Time to solve it:

~ 0.84 seconds

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