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Solve ((x^2-16)/(x-1))/((6x+8+x^2)/(2x-3+x^2))

\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}

Step by step solution

Problem

$\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$

Show full step-by-step solution

Answer

$\frac{\left(3+x\right)\left(x-4\right)}{2+x}$
$\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$

Main topic:

Factor by difference of squares

Used formulas:

0

Time to solve it:

0.34 seconds