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\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}

Solve ((x^2-16)/(x-1))/((6x+8+x^2)/(2x-3+x^2))

Answer

$\frac{3\left(x-4\right)+x\left(x-4\right)}{2+x}$

Step-by-step explanation

Problem

$\frac{\frac{x^2-16}{x-1}}{\frac{x^2+6x+8}{x^2+2x-3}}$
1

Simplifying the fraction

$\frac{-3+2x+x^2}{8+6x+x^2}\cdot\frac{x^2-16}{x-1}$

Unlock this step-by-step solution!

Answer

$\frac{3\left(x-4\right)+x\left(x-4\right)}{2+x}$

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