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Find the integral $\int\frac{2x^3}{2x^2-4x+3}dx$

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Final Answer

$\frac{1}{2}x^2+2x-\frac{5}{2}\ln\left(\frac{\frac{\sqrt{2}}{2}}{\sqrt{\frac{1}{2}+\left(x-1\right)^2}}\right)-\frac{\sqrt{2}}{2}\arctan\left(1.414201\left(x-1\right)\right)+C_0$
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Step-by-step Solution

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Take out the constant $2$ from the integral

$2\int\frac{x^3}{2x^2-4x+3}dx$

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$2\int\frac{x^3}{2x^2-4x+3}dx$

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Learn how to solve problems step by step online. Find the integral int((2x^3)/(2x^2-4x+3))dx. Take out the constant 2 from the integral. Divide x^3 by 2x^2-4x+3. Resulting polynomial. Expand the integral \int\left(\frac{1}{2}x+1+\frac{\frac{5}{2}x-3}{2x^2-4x+3}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately.

Final Answer

$\frac{1}{2}x^2+2x-\frac{5}{2}\ln\left(\frac{\frac{\sqrt{2}}{2}}{\sqrt{\frac{1}{2}+\left(x-1\right)^2}}\right)-\frac{\sqrt{2}}{2}\arctan\left(1.414201\left(x-1\right)\right)+C_0$

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Function Plot

Plotting: $\frac{1}{2}x^2+2x-\frac{5}{2}\ln\left(\frac{\frac{\sqrt{2}}{2}}{\sqrt{\frac{1}{2}+\left(x-1\right)^2}}\right)-\frac{\sqrt{2}}{2}\arctan\left(1.414201\left(x-1\right)\right)+C_0$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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