$\left(-\frac{2}{3}x^2+3y\right)^2$
$3x^2+3x-4=0$
$\frac{dy}{dx}=16y^2+81$
$6x^2+x-15+3x^4+5x^3$
$\log\left(x-1\right)+\log\left(x+1\right)=3\log\left(2\right)+\log\left(x-2\right)$
$-3x^2+6x-1=0$
$\frac{d}{dy}\:y=-18$
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