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Step-by-step Solution

Solve $5\left(\frac{x^2+3x+5}{2x-1}\right)\left(\frac{2x^2-2x-13}{4x^2-4x+1}\right)$

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Answer

$\frac{5\left(2x^2-2x-13\right)\left(5+x\left(x+3\right)\right)}{\left(2x-1\right)^{3}}$

Step-by-step explanation

Problem to solve:

$5\frac{x^2+3x+5}{2x-1}\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$
1

Multiplying the fraction and term

$\frac{2x^2-2x-13}{4x^2-4x+1}\cdot\frac{5\left(x^2+3x+5\right)}{2x-1}$
2

Multiplying fractions

$\frac{5\left(2x^2-2x-13\right)\left(x^2+3x+5\right)}{\left(4x^2-4x+1\right)\left(2x-1\right)}$

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Answer

$\frac{5\left(2x^2-2x-13\right)\left(5+x\left(x+3\right)\right)}{\left(2x-1\right)^{3}}$
$5\frac{x^2+3x+5}{2x-1}\cdot\frac{2x^2-2x-13}{4x^2-4x+1}$

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Time to solve it:

~ 1.13 seconds