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Step-by-step Solution

Find the derivative of $x^2+y+3xy^3=\frac{1-x}{x}$ using the constant rule

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Answer

$true$

Step-by-step explanation

Problem to solve:

$\frac{d}{dx}\left(x^2+y+3x y^3=\frac{1-x}{x}\right)$
1

Apply implicit differentiation by taking the derivative of both sides of the equation with respect to the differentiation variable

$\frac{d}{dx}\left(x^2+y+3xy^3\right)=\frac{d}{dx}\left(\frac{1-x}{x}\right)$
2

The derivative of the constant function is equal to zero

$0=\frac{d}{dx}\left(\frac{1-x}{x}\right)$

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Answer

$true$
$\frac{d}{dx}\left(x^2+y+3x y^3=\frac{1-x}{x}\right)$

Main topic:

Differential equations

Time to solve it:

~ 1.08 seconds