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\int\frac{10}{\sqrt{1-t^2}}dt

Integral of 10/((1-1t^2)^0.5)

Answer

$10arcsin\left(t\right)+C_0$

Step-by-step explanation

Problem

$\int\frac{10}{\sqrt{1-t^2}}dt$
1

Solve the integral $\int\frac{10}{\sqrt{1-t^2}}dt$ by trigonometric substitution using the substitution

$\begin{matrix}t=1\sin\left(\theta\right) \\ dt=\cos\left(\theta\right)d\theta\end{matrix}$

Unlock this step-by-step solution!

Answer

$10arcsin\left(t\right)+C_0$
$\int\frac{10}{\sqrt{1-t^2}}dt$

Main topic:

Integration by trigonometric substitution

Used formulas:

5. See formulas

Time to solve it:

~ 2.62 seconds