$8x+5x^2+2-3x-7$
$\lim\:_{k\to\:\infty\:}\left(\frac{\left(-6\right)^k-7\left(4^{2k-2}\right)}{3^{3k-3}}\right)$
$0.798+0.25+96+16.247+84.02$
$\left(x^2-x-5\right)\left(x^5-x^4+7x^2-27x+10\right)$
$4x+2-2x+3$
$2x^2+x-5=0$
$z^3+z^2+\frac{z}{3}+\frac{1}{27}$
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