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Solve the product $\left(-6x+3\right)\left(-6x-3\right)$

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 Solution

 Videos

Algebra 1 - Using the zero product property to solve (m-3)(m+5) = 0

https://www.youtube.com/watch?v=pF-yoDwTMiE

Learn how to apply the cross product to solve the proportion ex 10, (x - 5)/4 = 3/2

https://www.youtube.com/watch?v=IjMchGnPygY

Special products of the form (x+a)(x-a) | Algebra I | High School Math | Khan Academy

https://www.youtube.com/watch?v=JfuisfEdnjk

Polynomial special products: difference of squares | Algebra 2 | Khan Academy

https://www.youtube.com/watch?v=uNweU6I4Icw

U08_L2_T4_we3 Special Products of Polynomials 3

https://www.youtube.com/watch?v=jYfWFy0yxB4

Tutorial - Learn to write the first five terms of a geometric sequence ex 1, a1 = 3 and r = 3

https://www.youtube.com/watch?v=8Izp1SnHdwQ

 Function Plot

Plotting: $36x^2-9$

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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