$\frac{a\left(4a^2-8ab\right)}{x\left(3a^2-6ab\right)}$
$3\left(x-1\right)^2+1$
$-600+520-300-243+842$
$5\:\left(-16\::\:\left(21-13\right)\:-3\:\left(-7+15\right)\right)$
$\left(2x^3+3x\right)\left(2x^3-5x\right)$
$f\left(x\right)=\left(3-2x\right)^5$
$4h^2\cdot8h^{-3}\cdot3h^{-2}$
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