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Expand the integral $\int\left(x+\frac{3}{x^2-9}\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int xdx+\int\frac{3}{x^2-9}dx$
Learn how to solve integrals of polynomial functions problems step by step online. Integrate int(x+3/(x^2-9))dx. Expand the integral \int\left(x+\frac{3}{x^2-9}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int xdx results in: \frac{1}{2}x^2. The integral \int\frac{3}{x^2-9}dx results in: -\frac{1}{2}\ln\left(x+3\right)+\frac{1}{2}\ln\left(x-3\right). Gather the results of all integrals.