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Find the integral $\int\frac{2y+3}{-2y^2+1\cdot -6y+2}dy$

Step-by-step Solution

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Solving: $\int\frac{2y+3}{-2y^2+1\cdot -6y+2}dy$

Final Answer

$-\frac{1}{2}\ln\left(-y^2-3y+1\right)+C_0$
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Step-by-step Solution

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Simplifying

$\int\frac{2y+3}{-2y^2-6y+2}dy$

Learn how to solve sum rule of differentiation problems step by step online.

$\int\frac{2y+3}{-2y^2-6y+2}dy$

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Learn how to solve sum rule of differentiation problems step by step online. Find the integral int((2y+3)/(-2y^2+1*-6y+2))dy. Simplifying. Rewrite the expression \frac{2y+3}{-2y^2-6y+2} inside the integral in factored form. Take the constant \frac{1}{2} out of the integral. We can solve the integral \int\frac{2y+3}{-y^2-3y+1}dy by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that -y^2-3y+1 it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part.

Final Answer

$-\frac{1}{2}\ln\left(-y^2-3y+1\right)+C_0$

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Function Plot

Plotting: $-\frac{1}{2}\ln\left(-y^2-3y+1\right)+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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