$\int\left(x^2+3x\right)^4\left(2x+3\right)dx$

$\lim_{x\to\infty}\left(\frac{ln\left(7x+10\right)}{ln\left(3x+4\right)+6}\right)$

$9.5+8.6+4.9+4.9+4.8$

$\frac{-1x^3-x+5x^2-15}{x-3}$

$\int\frac{x^2-x-4}{\left(x+4\right)\left(x-2\right)}dx$

$\left(4x^2y^5\right)\left(-3x^3y^2\right)$

$\left(b^{-3}\right)\left(b^5\right)$