$p^2-10p+9$
$\left(2x^2-3x\right).\left(-x^2+4\right)+8-3x^4+12x$
$\left(3-abc\right)\left(abc+3\right)$
$\left(8b^6+k\right)^3$
$\:\left|\:-40\right|+8$
$\frac{\left(12x^2\right)}{\left(15y^2\right)}$
$c-c+c$
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