$\tan\left(2x+40^{\circ}\right)$
$2-\left\{-5-\left\{-4+4-7+9\right\}\right\}-11+25$
$b^5+5b^3$
$\frac{280}{x+2}=20+2.5x$
$\lim_{x\to\infty}\left(\frac{8x^3+4x^2+x}{9x^5-3x^3}\right)$
$\left(\frac{2}{5}+12k\right)^2$
$x^2+26x+88$
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