# Step-by-step Solution

## Integrate ln(((t*x)/7.3890560989306495))

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### Videos

$\frac{1}{t}\left(tx\ln\left(tx\right)-tx\right)-2x+C_0$

## Step-by-step explanation

Problem to solve:

$\int\frac{lntx}{e^2}dx$
1

The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator

$\int\left(\ln\left(tx\right)-1\ln\left(7.3891\right)\right)dx$
2

Calculating the natural logarithm of $7.3891$

$\int\left(\ln\left(tx\right)-12\right)dx$

$\frac{1}{t}\left(tx\ln\left(tx\right)-tx\right)-2x+C_0$
$\int\frac{lntx}{e^2}dx$