Final Answer
$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$
Step-by-step Solution
Problem to solve:
$order\left(m n^2 x^2-3m n^3\cdot x-2+\frac{1}{8} x^3,x,2\right)$
1
Apply the formula: $\mathrm{order}\left(x,a,b\right)$, where $a=x$, $b=2$ and $x=mn^2x^2-3mn^3x-2+\frac{1}{8}x^3$
$-2-3mn^3x+mn^2x^2+\frac{1}{8}x^3$
2
Factoring by $m$
$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$
Final Answer
$m\left(-3n^3x+n^2x^2\right)-2+\frac{1}{8}x^3$