$\frac{\left(2x+1\right)}{\left(x-1\right)\left(x+3\right)}=\frac{a}{x-1}+\frac{b}{x+3}$
$\int\frac{2x+1}{x^4+5x^2}dx$
$\int\frac{2x^4}{x^2+9}dx$
$h^2+10h-11=0$
$6m\:+16\:-10\:+5n$
$x^2-24x+78$
$40f^9g^6-60f^8g^4+80f^4g^3$
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