$100+5x+x^2$
$3x+21=72$
$9n-4+n=16$
$-4m-3n$
$\left|-10-12\right|$
$\lim_{x\to0}\left(x^3+1\right)^{\frac{1}{x}}$
$\left(\frac{5}{3}^{-3}\frac{5}{3}^{-2}\frac{5}{3}^5\right)^{12}$
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