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Find the derivative of $\left(\frac{6x^{\left(2-7x\right)}}{3x^3-2}\right)^2\left(2x+4\right)^3$

Step-by-step Solution

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Final Answer

$\frac{36\left(2x^{\left(2-7x\right)}\left(-7x\ln\left(x\right)+2-7x\right)x^{\left(1-7x\right)}\left(2x+4\right)^3+6\left(x^{\left(2-7x\right)}\right)^2\left(2x+4\right)^{2}\right)\left(3x^3-2\right)^2-648\left(x^{\left(2-7x\right)}\right)^2\left(3x^3-2\right)\left(2x+4\right)^3x^{2}}{\left(3x^3-2\right)^{4}}$
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Step-by-step Solution

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The power of a quotient is equal to the quotient of the power of the numerator and denominator: $\displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}$

$\frac{d}{dx}\left(\frac{\left(6x^{\left(2-7x\right)}\right)^2}{\left(3x^3-2\right)^2}\left(2x+4\right)^3\right)$

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$\frac{d}{dx}\left(\frac{\left(6x^{\left(2-7x\right)}\right)^2}{\left(3x^3-2\right)^2}\left(2x+4\right)^3\right)$

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Learn how to solve problems step by step online. Find the derivative of ((6x^(2-7x))/(3x^3-2))^2(2x+4)^3. The power of a quotient is equal to the quotient of the power of the numerator and denominator: \displaystyle\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n}. The power of a product is equal to the product of it's factors raised to the same power. Multiplying the fraction by \left(2x+4\right)^3. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}.

Final Answer

$\frac{36\left(2x^{\left(2-7x\right)}\left(-7x\ln\left(x\right)+2-7x\right)x^{\left(1-7x\right)}\left(2x+4\right)^3+6\left(x^{\left(2-7x\right)}\right)^2\left(2x+4\right)^{2}\right)\left(3x^3-2\right)^2-648\left(x^{\left(2-7x\right)}\right)^2\left(3x^3-2\right)\left(2x+4\right)^3x^{2}}{\left(3x^3-2\right)^{4}}$

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Function Plot

Plotting: $\frac{36\left(2x^{\left(2-7x\right)}\left(-7x\ln\left(x\right)+2-7x\right)x^{\left(1-7x\right)}\left(2x+4\right)^3+6\left(x^{\left(2-7x\right)}\right)^2\left(2x+4\right)^{2}\right)\left(3x^3-2\right)^2-648\left(x^{\left(2-7x\right)}\right)^2\left(3x^3-2\right)\left(2x+4\right)^3x^{2}}{\left(3x^3-2\right)^{4}}$

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0
a
b
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f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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