$4cos^2\left(x-1\right)=0$
$3a^3+6a^2+9a$
$\left(+14\right)-\left(-11\right)$
$\left(2x^2y^2\right)^2$
$\frac{3}{16\:}\:x\:\frac{40}{3}$
$\frac{x^4+x^6}{x^2-1}$
$a^2x^2+6ax^2y+9y^2$
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