$\int\left(x^3.\sqrt[3]{16+4x^2}\right)dx$
$81yn^2-72yn+16y^2n$
$u^{-8}\cdot u^4$
$\frac{-60x-36}{5x+3}$
$\frac{z}{6}=\frac{1}{2}$
$18+x^2-6x=0$
$x^3+11x^2+35x+25$
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