$372-4.y=980$
$2\left(3\right)^3\left(1\right)^3$
$\left(-5+6-2+1\right)-\left(-12+2+3\right)$
$3\left(3x\right)+3\left(6\right)$
$\left(x^2+4x-5\right)\left(x^2+4x+2\right)$
$5x^2+6x-12x^2-9x+2$
$\frac{\left(3x+8\right)}{\left(x^2+5x+6\right)}dx-\frac{\left(4y\right)}{\left(y^2+4\right)}dy\:=0$
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