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\frac{x^2-4x+4}{x-4}\geq 0

Solve the inequality (-4x+4+x^2)/(x-4)%0

Answer

$\frac{4-4x+x^2}{x-4}\geq 0$

Step-by-step explanation

Problem

$\frac{x^2-4x+4}{x-4}\geq 0$
1

Split the fraction $\frac{x^2-4x+4}{x-4}$ in two terms with same denominator

$\frac{4}{x-4}+\frac{x^2-4x}{x-4}\geq 0$

Unlock this step-by-step solution!

Answer

$\frac{4-4x+x^2}{x-4}\geq 0$