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Solve the inequality $\frac{1}{2}\left(x+1\right)-\frac{1}{3}\left(2x-5\right)>\frac{1}{4}\left(3-x\right)$

Step-by-step Solution

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Final Answer

$x>-17$
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Step-by-step Solution

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Multiply the single term $\frac{1}{2}$ by each term of the polynomial $\left(x+1\right)$

$\frac{1}{2}x+\frac{1}{2}-\frac{1}{3}\left(2x-5\right)>\frac{1}{4}\left(3-x\right)$

Learn how to solve differential calculus problems step by step online.

$\frac{1}{2}x+\frac{1}{2}-\frac{1}{3}\left(2x-5\right)>\frac{1}{4}\left(3-x\right)$

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Learn how to solve differential calculus problems step by step online. Solve the inequality 1/2(x+1)-1/3(2x-5)>1/4(3-x). Multiply the single term \frac{1}{2} by each term of the polynomial \left(x+1\right). Multiply the single term -\frac{1}{3} by each term of the polynomial \left(2x-5\right). Add the values \frac{1}{2} and \frac{5}{3}. Combining like terms \frac{1}{2}x and -\frac{2}{3}x.

Final Answer

$x>-17$

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Function Plot

Plotting: $x>-17$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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