Final Answer
Step-by-step Solution
Specify the solving method
Divide $2x^2+16x+22$ by $x^2+6x+10$
Learn how to solve integrals of rational functions problems step by step online.
$\begin{array}{l}\phantom{\phantom{;}x^{2}+6x\phantom{;}+10;}{\phantom{;}2\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+6x\phantom{;}+10\overline{\smash{)}\phantom{;}2x^{2}+16x\phantom{;}+22\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+6x\phantom{;}+10;}\underline{-2x^{2}-12x\phantom{;}-20\phantom{;}\phantom{;}}\\\phantom{-2x^{2}-12x\phantom{;}-20\phantom{;}\phantom{;};}\phantom{;}4x\phantom{;}+2\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve integrals of rational functions problems step by step online. Find the integral int((2x^2+16x+22)/(x^2+6x+10))dx. Divide 2x^2+16x+22 by x^2+6x+10. Resulting polynomial. Expand the integral \int\left(2+\frac{4x+2}{x^2+6x+10}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int2dx results in: 2x.