$2x^2+3x-4-x^2+x+x$
$x-x^{-1}=2$
$\frac{1-\frac{1}{cos\left(x\right)}}{tan\left(x\right)}=\frac{cos\left(x\right)}{sin\left(x\right)}$
$\frac{16x^3+4x^2}{4x^2}$
$\frac{x}{3}^3+2$
$\lim_{x\to4}\left(\frac{\tan\left(9x\left(x-4\right)\right)}{x-4}\right)$
$x^2yz\:+\:3xy^2z\:-\:2xyz^2\:-\:3xy^2z\:+\:xyz^2\:-\:x^2yz$
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