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Find the integral $\int\frac{1+\frac{\sqrt{x}}{2}}{1+\frac{\sqrt{x}}{3}}dx$

Step-by-step Solution

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Final Answer

$\frac{3}{2}x-3\sqrt{x}+9\ln\left(\sqrt{x}+3\right)+C_0$
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Step-by-step Solution

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Simplify the expression inside the integral

$3\int\frac{\sqrt{x}+2}{2\left(\sqrt{x}+3\right)}dx$

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$3\int\frac{\sqrt{x}+2}{2\left(\sqrt{x}+3\right)}dx$

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Learn how to solve problems step by step online. Find the integral int((1+(x^1/2)/2)/(1+(x^1/2)/3))dx. Simplify the expression inside the integral. Take the constant \frac{1}{2} out of the integral. Multiply 3 times \frac{1}{2}. We can solve the integral \int\frac{\sqrt{x}+2}{\sqrt{x}+3}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that \sqrt{x} it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part.

Final Answer

$\frac{3}{2}x-3\sqrt{x}+9\ln\left(\sqrt{x}+3\right)+C_0$

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Function Plot

Plotting: $\frac{3}{2}x-3\sqrt{x}+9\ln\left(\sqrt{x}+3\right)+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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