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{\frac{-19t+32}{6t-7}}\geq {-4}

Solve the inequality (-19t+32)/(6t-7)%-4

Answer

$\frac{28-24t}{19}+t\leq \frac{32}{19}$

Step-by-step explanation

Problem

${\frac{-19t+32}{6t-7}}\geq {-4}$
1

Moving the denominator multiplying to the other side of the inequation

$32-19t\geq -4\left(6t-7\right)$

Unlock this step-by-step solution!

Answer

$\frac{28-24t}{19}+t\leq \frac{32}{19}$