$\frac{1+\tan\left(a\right)^2}{\sec\left(a\right)}$
$\left(2x+3y\right)y^'=\left(2x-3y\right)$
$7a+10=-18$
$\int y\sqrt{3y+1}dy$
$2\left(x+1\right)^2-4=x\left(x+3\right)$
$\sqrt[6]{\left(\sqrt{m^2}n^4\right)}\left(\sqrt{m^4n^2}\right)$
$\sqrt[3]{81x^2y^4}$
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