$\lim_{x\to6}\left(\frac{x-6}{\left(\sqrt{x+3}-3\right)}\right)$
$\frac{x-4}{3x}+1\frac{x+4}{x}$
$\frac{d}{dx}y=\frac{6}{y^3}-2x$
$x^2+2y+2=0$
$-\sqrt{48}+11\sqrt{3}$
$\int\frac{1}{x\left(x+1\right)^{\frac{1}{2}}}dx$
$\int\left(x^5\left(t^6+1\right)^4\right)dx$
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