# Step-by-step Solution

## Integrate 4t^(1/3)+t(t^2+1)^3 from 1 to 2

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## Step-by-step explanation

Problem to solve:

$\int_1^2\left[4t^{\left(1/3\right)}+t\left(t^2+1\right)^3\right]dt$
1

The integral of a sum of two or more functions is equal to the sum of their integrals

$\int_{1}^{2}4\sqrt[3]{t}dt+\int_{1}^{2} t\left(t^2+1\right)^3dt$
2

Sacar la parte constante de la integral

$4\int_{1}^{2}\sqrt[3]{t}dt+\int_{1}^{2} t\left(t^2+1\right)^3dt$

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$\int_1^2\left[4t^{\left(1/3\right)}+t\left(t^2+1\right)^3\right]dt$