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Integral of (1-3x)/(2x-8+x^2)

\int\frac{1-3x}{x^2+2x-8}dx

Step by step solution

Problem

$\int\frac{1-3x}{x^2+2x-8}dx$

Show full step-by-step solution

Answer

$-\frac{13}{6}\ln\left|4+x\right|-\frac{5}{6}\ln\left|x-2\right|+C_0$
$\int\frac{1-3x}{x^2+2x-8}dx$

Main topic:

Integrals by partial fraction expansion

Used formulas:

2. See formulas

Time to solve it:

0.47 seconds