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\frac{d}{dx}\left(x^2y+3x y^3=\frac{111\left(-1\right)}{x^2}\right)

Find the derivative of x^2y+xy^3*3=(111*-1)/(x^2)

Answer

$3y^3+y\frac{d}{dx}\left(x^2\right)=\frac{111\frac{d}{dx}\left(x^2\right)}{x^{4}}$

Step-by-step explanation

Problem

$\frac{d}{dx}\left(x^2y+3x y^3=\frac{111\left(-1\right)}{x^2}\right)$
1

Multiply $111$ times $-1$

$\frac{d}{dx}\left(3y^3x+y\cdot x^2=\frac{-111}{x^2}\right)$

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Answer

$3y^3+y\frac{d}{dx}\left(x^2\right)=\frac{111\frac{d}{dx}\left(x^2\right)}{x^{4}}$

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$\frac{d}{dx}\left(x^2y+3x y^3=\frac{111\left(-1\right)}{x^2}\right)$

Main topic:

Differential calculus

Used formulas:

4. See formulas

Time to solve it:

~ 2.12 seconds