Final Answer
Step-by-step Solution
Specify the solving method
Divide fractions $\frac{-1}{\frac{2x^2-x-3}{x^3+2x^2+6x+5}}$ with Keep, Change, Flip: $a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}$
Learn how to solve problems step by step online.
$\frac{-\left(x^3+2x^2+6x+5\right)}{2x^2-x-3}$
Learn how to solve problems step by step online. Simplify the expression -1/((2x^2-x+-3)/(x^3+2x^26x+5)). Divide fractions \frac{-1}{\frac{2x^2-x-3}{x^3+2x^2+6x+5}} with Keep, Change, Flip: a\div \frac{b}{c}=\frac{a}{1}\div\frac{b}{c}=\frac{a}{1}\times\frac{c}{b}=\frac{a\cdot c}{b}. We can factor the polynomial \left(x^3+2x^2+6x+5\right) using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 5. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial \left(x^3+2x^2+6x+5\right) will then be.