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Combine $\frac{1}{x^2-4x+4}-0.25$ in a single fraction
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$\frac{1-0.25\left(x^2-4x+4\right)}{x^2-4x+4}$
Learn how to solve integral calculus problems step by step online. Simplify 1/(x^2-4x+4)-1/4. Combine \frac{1}{x^2-4x+4}-0.25 in a single fraction. Multiply the single term -\frac{1}{4} by each term of the polynomial \left(x^2-4x+4\right). Multiply -4 times -0.25. Multiply 4 times -0.25.