$=\frac{1}{-2x^2-6x-4}$
$\log\left(x\right)+\log\left(x+1\right)=\log\left(20\right)$
$\lim_{x\to0}\:\frac{ln\left(6x+1\right)}{sin\left(x\right)}$
$\int_1^{\infty}\left(\frac{4lnx}{x^2}\right)dx$
$-98-56+-14$
$x^2+9x-10$
$\frac{x^4+2}{x^2+2x+5}$
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