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Integrate the function $\frac{x^2+8}{x^2}$ from $2$ to $4$

Step-by-step Solution

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Final Answer

$4$
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Step-by-step Solution

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1

Expand the fraction $\frac{x^2+8}{x^2}$ into $2$ simpler fractions with common denominator $x^2$

$\int_{2}^{4}\left(\frac{x^2}{x^2}+\frac{8}{x^2}\right)dx$

Learn how to solve definite integrals problems step by step online.

$\int_{2}^{4}\left(\frac{x^2}{x^2}+\frac{8}{x^2}\right)dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function (x^2+8)/(x^2) from 2 to 4. Expand the fraction \frac{x^2+8}{x^2} into 2 simpler fractions with common denominator x^2. Simplify the resulting fractions. Expand the integral \int_{2}^{4}\left(1+\frac{8}{x^2}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{2}^{4}1dx results in: 2.

Final Answer

$4$

Exact Numeric Answer

$4$

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Function Plot

Plotting: $\frac{x^2+8}{x^2}$

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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

3. See formulas

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