$\left(x+1\right)^3-\left(y-2\right)^3=0$
$\frac{dy}{dx}=\frac{y+x\frac{\cos\left(\frac{y}{x}\right)}{\sin\left(\frac{y}{x}\right)}}{x}$
$x^2-0.36$
$5\cdot3\cdot7-9$
$\frac{d^2}{dx^2}\left(\:2x^4\:+\:3x^2\:+4x\:+\:9\right)$
$\frac{2^6}{2}$
$3y+1y$
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