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Find the integral $\int\frac{x+3}{x^2+4x+5}dx$

Step-by-step Solution

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Final Answer

$\arctan\left(x+2\right)+\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)+C_0$
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Step-by-step Solution

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1

Rewrite the expression $\frac{x+3}{x^2+4x+5}$ inside the integral in factored form

$\int\frac{x+3}{1+\left(x+2\right)^2}dx$
2

We can solve the integral $\int\frac{x+3}{1+\left(x+2\right)^2}dx$ by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it $u$), which when substituted makes the integral easier. We see that $x+2$ it's a good candidate for substitution. Let's define a variable $u$ and assign it to the choosen part

$u=x+2$
3

Now, in order to rewrite $dx$ in terms of $du$, we need to find the derivative of $u$. We need to calculate $du$, we can do that by deriving the equation above

$du=dx$
4

Rewriting $x$ in terms of $u$

$x=u-2$
5

Substituting $u$, $dx$ and $x$ in the integral and simplify

$\int\frac{1+u}{1+u^2}du$
6

Expand the fraction $\frac{1+u}{1+u^2}$ into $2$ simpler fractions with common denominator $1+u^2$

$\int\left(\frac{1}{1+u^2}+\frac{u}{1+u^2}\right)du$
7

Expand the integral $\int\left(\frac{1}{1+u^2}+\frac{u}{1+u^2}\right)du$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$\int\frac{1}{1+u^2}du+\int\frac{u}{1+u^2}du$
8

The integral $\int\frac{1}{1+u^2}du$ results in: $\arctan\left(x+2\right)$

$\arctan\left(x+2\right)$
9

The integral $\int\frac{u}{1+u^2}du$ results in: $\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)$

$\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)$
10

Gather the results of all integrals

$\arctan\left(x+2\right)+\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)$
11

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$\arctan\left(x+2\right)+\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)+C_0$

Final Answer

$\arctan\left(x+2\right)+\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)+C_0$

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Function Plot

Plotting: $\arctan\left(x+2\right)+\frac{1}{2}\ln\left(1+\left(x+2\right)^2\right)+C_0$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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