$8x-4>3x-9$
$\frac{4x-3x+14x}{8}$
$\left(3x^4-7x+4\right)^2$
$5=x^2-4$
$-2x+1-2x+4$
$-12x^5y^2\left(10x^3y^4\right)$
$-\left(-29\right)+\left(-37\right)-\left(-30\right)-\left(-80\right)$
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