$-35\cdot\left(-4\right)$
$\frac{1}{3}x^2-2x+4=0$
$y=\ln\left[\left(3x^4-2\right)^{tanx}\right]$
$\cos\cos\left(t\right)+2$
$-749.\:865\:x\:-35$
$\left(18m^3\right)^2$
$5\le y+6$
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