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y''+y=\cot\left(2x\right)

Solve the equation y''+y=cot(2*x)

Answer

$y-\left(\frac{1-2\sin\left(x\right)^2}{\sin\left(2x\right)}\right)=-1\cdot y''$

Step-by-step explanation

Problem to solve:

$y''+y=\cot\left(2x\right)$
1

Applying the cotangent identity: $\displaystyle\cot\left(\theta\right)=\frac{\cos\left(\theta\right)}{\sin\left(\theta\right)}$

$y''+y=\frac{\cos\left(2x\right)}{\sin\left(2x\right)}$
2

Applying an identity of double-angle cosine

$y''+y=\frac{1-2\sin\left(x\right)^2}{\sin\left(2x\right)}$

Unlock this step-by-step solution!

Answer

$y-\left(\frac{1-2\sin\left(x\right)^2}{\sin\left(2x\right)}\right)=-1\cdot y''$
$y''+y=\cot\left(2x\right)$

Main topic:

Equations

Time to solve it:

~ 0.65 seconds

Related topics:


Equations